3.5选择判断的机器人女友案例

这个博客展示了一个简单的C程序,模拟了选择机器人女友的标准,包括健康状况、外貌和财富条件。如果满足所有条件,程序将表示可以成为朋友,否则将拒绝。该程序涉及条件判断和用户输入交互。

3.5选择判断的机器人女友案例

#include<stdio.h>

/*	3.4
	author:edcfreedom
	date:2021/8/6
	funDescription:
		经典案例
*/

int main()
{
	int healthYesOrNot;
	int handsome;
	int richYesOrNot;
	int spendMoneyForMe;
	
	printf("Would you have a healthy body?\n");
	scanf("%d",&healthYesOrNot);
	
	if( healthYesOrNot ==1){
		printf("we can become friend\n");
		puts("Whether or not handsome ,and rich?(tips:请输入两个整数)");
		scanf("%d%d",&handsome,&richYesOrNot);
		if(handsome == 1 && richYesOrNot == 1){
			printf("We still friend\n");
			printf("Would you willing spend money for me?\n");
			scanf("%d",&spendMoneyForMe);
			if(spendMoneyForMe == 1){
				printf("So, we can make xx\n");
			}else{
				printf("You are so mean,886!\n");
			}
		}else{
			printf("Not healthy body, and rich,don't contact with me!\n");
		}
	}else{
		printf("Sorry, you don't have a healthy body, we cannot become friend\n");
	}
	
	return 0;
}
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值