3.3 逻辑判断与或非
#include<stdio.h>
/* 3.2
author:edcfreedom
date:2021/8/6
funDescription:
logic,与、或、非、Money,handsome
*/
int main()
{
int haveMoneyOrNot;
int handsomeOrNot;
int puTianYesOrNot;
puts("你是莆田的吗?不是的话扣1,是的话扣0");
scanf("%d",&puTianYesOrNot);
if( !puTianYesOrNot ){
printf("好女不嫁莆田男\n");
return -1;
}
puts("你有钱吗?有钱扣1,没钱扣0");
scanf("%d",&haveMoneyOrNot);
puts("你帅吗?帅扣1,不帅扣0");
scanf("%d",&handsomeOrNot);
if(haveMoneyOrNot == 1 && handsomeOrNot == 1){
printf("你真棒,我愿意!\n");
}
printf("相亲结束\n");
return 0;
}
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