3.3 逻辑判断与或非

3.3 逻辑判断与或非

#include<stdio.h>
/*	3.2
	author:edcfreedom
	date:2021/8/6
	funDescription:
		logic,与、或、非、Money，handsome
*/
int main()
{
	int haveMoneyOrNot;
	int handsomeOrNot;
	int puTianYesOrNot;
	
	puts("你是莆田的吗？不是的话扣1，是的话扣0");
	scanf("%d",&puTianYesOrNot);
	if( !puTianYesOrNot ){
		printf("好女不嫁莆田男\n");
		return -1;
		
	}
	
	puts("你有钱吗？有钱扣1，没钱扣0");
	scanf("%d",&haveMoneyOrNot);
	
	puts("你帅吗？帅扣1，不帅扣0");
	scanf("%d",&handsomeOrNot);
	
	if(haveMoneyOrNot == 1 && handsomeOrNot == 1){
		printf("你真棒，我愿意！\n");
	}
	
	printf("相亲结束\n");
	
	return 0;
}