#include <cstdio>
#include <cmath>
#define F(x) (p*exp(-x)+q*sin(x)+r*cos(x)+s*tan(x)+t*(x)*(x)+u)
const double eps = 1e-14;
int main(int argc, char const *argv[])
{
int p, r, q, s, t, u;
while (scanf("%d%d%d%d%d%d", &p, &q, &r, &s, &t, &u) == 6)
{
double f0 = F(0), f1 = F(1);
if (f1 > eps || f0 < -eps) printf("No solution\n");
else
{
double x = 0, y = 1, m;
for (int i = 0; i < 100; i++)
{
m = x + (y - x) / 2;
if (F(m) < 0) y = m; else x = m;
}
printf("%.4lf\n", m);
}
}
return 0;
}
要求的跟是0~1之间, 而且这个方程是单调递减的,所以可以用二分来求根。