1005. Spell It Right (20)

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本程序解决 SpellItRight 问题，读取非负整数 N，计算各位数字之和，并将该和的每一位用英文单词输出。输入为一行非负整数，输出为该整数各位相加后的和的每一位对应的英文单词。

1005. Spell It Right (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10¹⁰⁰).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

Sample Output:

one five

代码如下：

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
void show(int n)
{
	switch(n){
		case 0:	printf("zero"); break;
		case 1:	printf("one"); break;
		case 2:	printf("two"); break;
		case 3:	printf("three"); break;
		case 4:	printf("four"); break;
		case 5:	printf("five"); break;
		case 6:	printf("six"); break;
		case 7:	printf("seven"); break;
		case 8:	printf("eight"); break;
		case 9:	printf("nine"); break;
		default:break;

	}
}
int main()
{
    char str[100000];
    int i,j;
    int sum;
    int temp;
    int len;
    while(scanf("%s",str)!=EOF)
    {
	 sum = 0;
	 len = strlen(str);
	 for(i=0;i<len;i++)
         {
            temp = str[i]-'0';
            sum += temp;
	 }
	 i = 0;
	 while(sum!=0)
	 {
		 str[i++] = (sum%10+'0');
		 sum = sum/10;
	 }
	 for(j=i-1;j>0;j--){
		 show(str[j]-'0');
		 printf(" ");
	 }
	 show(str[0]-'0');
	 printf("\n");
    }
	return 0;
}