1018 锤子剪刀布题解

1018 锤子剪刀布题解

题目分析

题目本身很无脑了，按照题意编写程序即可。
刚开始又动了map的念头，其实无脑if判断就可以。分不同的情况，添加一个胜负记录器，添加一个手势判断数组。

我的代码

#include<iostream>
#include<map> 
#include<string>
#include<cmath>


int main()
{
	using namespace std;
	int number;
	char jia,yi;
	int yiwin=0,jiawin=0;
	int jiashou[3]={0,0,0};//0-c 1-j 2-b
	int yishou[3]={0,0,0}; //0-c 1-j 2-b
	cin>>number;
	for(int i=0;i<number;i++)
	{
	  cin>>jia>>yi;
	  if(jia=='C'&&yi=='C')
	  ;
	  if(jia=='J'&&yi=='J')
	  ;
	  if(jia=='B'&&yi=='B')
	  ;
	  if(jia=='C'&&yi=='J')
	  {
	  jiawin++;
	  jiashou[1]++;
      }  
	  if(jia=='C'&&yi=='B')
	  {
	  	yiwin++;
	  	yishou[0]++;
       }
       if(jia=='J'&&yi=='C')
       {
       	 yiwin++;
	     yishou[1]++;
	   }
	   if(jia=='J'&&yi=='B')
	   {
	   	jiawin++;
	   	jiashou[2]++;
	   }
	   if(jia=='B'&&yi=='C')
	   {
	   	jiawin++;
	   	jiashou[0]++;
	   }
	   if(jia=='B'&&yi=='J')
	   {
	   	yiwin++;
	   	yishou[2]++;
	   }	   
	}
	cout<<jiawin<<" "<<(number-jiawin-yiwin)<<" "<<yiwin<<endl;
	cout<<yiwin<<" "<<(number-jiawin-yiwin)<<" "<<jiawin<<endl;
	int maxjia=jiashou[0]>=jiashou[1]?0:1;
	maxjia=jiashou[maxjia]>=jiashou[2]?maxjia:2;
	int maxyi=yishou[0]>=yishou[1]?0:1;
	maxyi=yishou[maxyi]>=yishou[2]?maxyi:2;
	char str[4]={"BCJ"};
	cout << str[maxjia] << " " << str[maxyi];
    return 0;
}