题目大意:
给出骨头的价值和重量,用体积为V的背包装这些骨头,求最大价值
大致思路:
这里为01背包的讲解
http://blog.youkuaiyun.com/Remilitarize/article/details/55666889
C:(二维数组)
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
const int maxn=1010;
int value[maxn],weight[maxn];
int dp[maxn][maxn];
int main(){
int n;
while(scanf("%d",&n)!=EOF){
while(n--){
int a,b,i,j;
scanf("%d%d",&a,&b); //a为骨头数量,b为背包容量
memset(dp,0,sizeof(dp)); //初始化
for(i=1;i<=a;i++)
scanf("%d",&value[i]);
for(i=1;i<=a;i++)
scanf("%d",&weight[i]);
for(i=1;i<=a;i++) //选取第i个骨头
for(j=0;j<=b;j++) //当前背包容量为j
if(j>=weight[i]) //如果第i个骨头能够装入背包
dp[i][j]=max(dp[i-1][j],dp[i-1][j-weight[i]]+value[i]);
/*不装骨头为dp[i-1][j],
装骨头为把第i个骨头的重量去掉对应容量的dp[i-1][j-weight[i]并加上这个骨头的价值value[i]*/
else
dp[i][j]=dp[i-1][j];
printf("%d\n",dp[a][b]);
//a个骨头全部装进去并当前容量为b的最大价值
}
}
return 0;
}
C:(一维数组)
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
const int maxn=1010;
int value[maxn],weight[maxn];
int dp[maxn];
int main(){
int n;
while(scanf("%d",&n)!=EOF){
while(n--){
int a,b,i,j;
scanf("%d%d",&a,&b);
memset(dp,0,sizeof(dp));
for(i=1;i<=a;i++)
scanf("%d",&value[i]);
for(i=1;i<=a;i++)
scanf("%d",&weight[i]);
for(i=1;i<=a;i++)
for(j=b;j>=weight[i];j--) //注意要从后向前
dp[j]=max(dp[j],dp[j-weight[i]]+value[i]);
printf("%d\n",dp[b]);
}
}
return 0;
}