The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...
1
is read off as "one
1"
or 11
.
11
is read off as "two
1s"
or 21
.
21
is read off as "one
2
, then one 1"
or 1211
.
Given an integer n, generate the nth sequence.
Note: The sequence of integers will be represented as a string.
样例输出:
1. 1
2. 11
3. 21
4. 1211
5. 111221
6. 312211
7. 13112221
8. 1113213211
9. 31131211131221
10. 13211311123113112211
自己的解答:
public String countAndSay(int n) {
if (n == 1) {
return "1";
}
String str = countAndSay(n-1);
StringBuilder sb = new StringBuilder();
int i, count;
for (i = 1; i < str.length(); i++) {
count = 0;
while (i == 0 || (i < str.length() && str.charAt(i) == str.charAt(i-1))) {
count++;
i++;
}
sb.append(count);
sb.append(str.charAt(i-1));
}
return sb.toString();
}
见到一个比较好的解答:
public String countAndSay(int n) {
StringBuilder curr=new StringBuilder("1");
StringBuilder prev;
int count;
char say;
for (int i=1;i<n;i++){
prev=curr;
curr=new StringBuilder();
count=1;
say=prev.charAt(0);
for (int j=1,len=prev.length();j<len;j++){
if (prev.charAt(j)!=say){
curr.append(count).append(say);
count=1;
say=prev.charAt(j);
}
else count++;
}
curr.append(count).append(say);
}
return curr.toString();
}
程序的目的就是为了模拟现实,把手动计算计算机化,就基本是一段不错的思路。。。比较上面的代码,先记录say的数字,然后count,不错。。。。
写代码就是为了模拟现实。。。