Leetcode 412. Fizz Buzz
思路:模拟(简单)
class Solution {
public:
vector<string> fizzBuzz(int n) {
vector<string> res;
for (int i = 1; i <= n; i ++ ) {
if (i % 3 == 0 && i % 5 == 0) res.push_back("FizzBuzz");
else if (i % 3 == 0) res.push_back("Fizz");
else if (i % 5 == 0) res.push_back("Buzz");
else res.push_back(to_string(i));
}
return res;
}
};