Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
For example,
Given input array nums = [1,1,2],
Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively.
It doesn't matter what you leave beyond the new length.
简单的双指针问题。
class Solution {
public:
//双指针
void Swap(int &a, int &b)
{
int tmp = a;
a = b;
b = tmp;
}
int removeDuplicates(vector<int>& nums) {
int len = nums.size();
if (len < 2)
return len;
int low = 0, high = 1;
while (high < len)
{
if(nums[high] != nums[low])
Swap(nums[++low], nums[high]);
++high;
}
return low + 1;
}
};
本文介绍了一个简单的方法来移除已排序数组中的重复元素,并保持每个元素只出现一次。使用双指针技术实现,不使用额外的空间,符合常数内存限制。
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