Anagram // 深度优先搜索 (代码不正确)

本文介绍了一个算法问题,即如何从给定的一组字母中生成所有可能的单词组合,并确保输出结果既不会重复也不会遗漏,同时要求输出结果按字母顺序排列。文章提供了尝试解决此问题的代码示例,但代码存在问题,期待读者指正。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >


You are to write a program that has to generate all possible words from a given set of letters.
Example: Given the word "abc", your program should - by exploring all different combination of the three letters - output the words "abc", "acb", "bac", "bca", "cab" and "cba".
In the word taken from the input file, some letters may appear more than once. For a given word, your program should not produce the same word more than once, and the words should be output in alphabetically ascending order.

Input

The input consists of several words. The first line contains a number giving the number of words to follow. Each following line contains one word. A word consists of uppercase or lowercase letters from A to Z. Uppercase and lowercase letters are to be considered different. The length of each word is less than 13.

Output

For each word in the input, the output should contain all different words that can be generated with the letters of the given word. The words generated from the same input word should be output in alphabetically ascending order. An upper case letter goes before the corresponding lower case letter.

Sample Input

3
aAb
abc
acba

Sample Output

Aab
Aba
aAb
abA
bAa
baA
abc
acb
bac
bca
cab
cba
aabc
aacb
abac
abca
acab
acba
baac
baca
bcaa
caab
caba
cbaa

Hint

An upper case letter goes before the corresponding lower case letter.
So the right order of letters is 'A'<'a'<'B'<'b'<...<'Z'<'z'.

Source

[Submit]   [Go Back]   [Status]   [Discuss]

望大佬能指点一二,改了好久,总是不正



注:代码存在错误,第三个样例的输出结果缺少输出的种类

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<iostream>
#include<algorithm>
#include<math.h>
using namespace std;
#define maxn 20
char ch[maxn];
string ss;
char ss2[maxn];
int len;
int visited[maxn];
int val(char c)
{
    if(c>='A'&& c<='Z')
        return 2*(c-'A');
    else
        return 2*(c-'a')+1;
}
bool cmp(char a,char b)
{
    return val(a)<val(b);
}

void  dfs(int  x)
{
    char flag;
    if(x==len)
    {
        ch[x]=0;
        puts(ch);
        return ;
    }
    else
    {
        for(int i=0;i<len;i++)
        {
            if(flag==ss2[i])
                continue;
            if(visited[i]==0)
            {
                visited[i]=1;
                ch[x]=ss2[i];
                flag=ch[x];
                dfs(x+1);
                visited[i]=0;
            }
        }
    }
}
int main()
{
   int t;
  scanf("%d",&t);
       while(t--)
       {
           memset(visited,0,sizeof(visited));
           cin>>ss2;
           len=strlen(ss2);
           sort(ss2,ss2+len,cmp);
           //puts(ss2);
           dfs(0);
       }

   return 0;
}

注::代码超时                                                                                                                         


#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<iostream>
#include<algorithm>
#include<math.h>
using namespace std;
#define maxn 20
char ch[maxn];
string ss;
char ss2[maxn];
int len;
int visited[maxn];
int val(char c)
{
    if(c>='A'&& c<='Z')
        return 2*(c-'A');
    else
        return 2*(c-'a')+1;
}
bool cmp(char a,char b)
{
    return val(a)<val(b);
}
/*void dfs(int x){
	if(x==len){
	  char str[15];
	  for(int i=0;i<len;++i)
	  printf("%c",ch[i]);
	  printf("\n");
	}
	else{
		for(int i=0;i<len;++i){
			if(!visted[i]){
			  ch[x]=ss[i];
			  visted[i]=1;
			  dfs(x+1);
			  visted[i]=0;
			  while(i+1<len&&ss[i+1]==ss[i])i++;
			}
		}
	}
}*/
void  dfs(int x)
{
    if(x==len)
    {
        for(int i=0;i<len;i++)
        {
            printf("%c",ch[i]);
        }
        printf("\n");
    }
    else
    {
        for(int i=0;i<len;i++)
        {
            if(visited[i]==0)
            {
                ch[x]=ss2[i];
                visited[i]=1;
                dfs(x+1);
                visited[i]=0;
                while((i+1)<len && ss2[i+1]==ss2[i])
                    i++;
            }
        }
    }
}
int main()
{
   int t;
   while(scanf("%d",&t)!=EOF)
   {
       while(t--)
       {
           memset(visited,0,sizeof(visited));
           getchar();
           cin>>ss2;
           len=strlen(ss2);
           sort(ss2,ss2+len,cmp);
           //puts(ss2);
           dfs(0);
       }
   }
   return 0;
}

 望大佬能指点一二,改了好久,总是不正



评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值