重建二叉树
https://www.nowcoder.com/practice/8a19cbe657394eeaac2f6ea9b0f6fcf6
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
/**
* NC12 重建二叉树
* @author d3y1
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
* 程序入口
*
* 递归: 前序遍历
*
* @param preOrder int整型一维数组
* @param vinOrder int整型一维数组
* @return TreeNode类
*/
public TreeNode reConstructBinaryTree (int[] preOrder, int[] vinOrder) {
int num = preOrder.length;
if(num == 0){
return null;
}
// 当前根结点
int rootVal = preOrder[0];
TreeNode root = new TreeNode(rootVal);
// 当前根结点 左子树节点个数
int left = 0;
while(vinOrder[left] != rootVal){
left++;
}
if(left > 0){
// int[] pre = new int[left];
// int[] vin = new int[left];
// System.arraycopy(preOrder, 1, pre, 0, left);
// System.arraycopy(vinOrder, 0, vin, 0, left);
// root.left = reConstructBinaryTree(pre, vin);
root.left = reConstructBinaryTree(Arrays.copyOfRange(preOrder, 1, left+1), Arrays.copyOfRange(vinOrder, 0, left));
}
// 当前根结点 右子树节点个数
int right = num-(left+1);
if(right > 0){
// int[] pre = new int[right];
// int[] vin = new int[right];
// System.arraycopy(preOrder, left+1, pre, 0, right);
// System.arraycopy(vinOrder, left+1, vin, 0, right);
// root.right = reConstructBinaryTree(pre, vin);
root.right = reConstructBinaryTree(Arrays.copyOfRange(preOrder, left+1, num), Arrays.copyOfRange(vinOrder, left+1, num));
}
return root;
}
}