LeetCode-Binary Tree Maximum Path Sum

最新推荐文章于 2024-03-25 21:39:45 发布

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最新推荐文章于 2024-03-25 21:39:45 发布

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分类专栏： Cracking LeetCode Tree Recursion 文章标签： leetcode Binary Tree Maximum

本文链接：https://blog.youkuaiyun.com/HolyDominat/article/details/38332941

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本文探讨了如何在二叉树中找到最大的路径和。通过递归方法，我们能够有效地解决这个问题，理解其背后的算法逻辑。

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Given a binary tree, find the maximum path sum.

The path may start and end at any node in the tree.

For example:
Given the below binary tree,

       1
      / \
     2   3

Return 6.

Solution:

Code:

<span style="font-size:14px;">/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    int helper(TreeNode *root, int &result) {
       if (!root) return 0;
       int left = helper(root->left, result);
       int right = helper(root->right, result);
       result = max(result, root->val+max(0, left)+max(0, right));
       left = max(left, right);
       return root->val+max(0, left);
    }
    
    int maxPathSum(TreeNode *root) {
        if (!root) return 0;
        int result = root->val;
        helper(root, result);
        return result;
    }
};</span>