题目链接
https://www.patest.cn/contests/gplt/L1-008
AC代码
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <cstring>
#include <map>
#include <stack>
#include <set>
#include <cstdlib>
#include <ctype.h>
#include <numeric>
#include <sstream>
using namespace std;
typedef long long LL;
const double PI = 3.14159265358979323846264338327;
const double E = 2.718281828459;
const double eps = 1e-6;
const int MAXN = 0x3f3f3f3f;
const int MINN = 0xc0c0c0c0;
const int maxn = 1e5 + 5;
const int MOD = 1e9 + 7;
int main()
{
int a, b;
cin >> a >> b;
int sum = 0;
int vis;
for (vis = 1; a <= b; a++, vis++)
{
printf("%5d", a);
sum += a;
if (vis % 5 == 0)
cout << endl;
}
if ((vis - 1) % 5 != 0)
cout << endl;
printf("Sum = %d\n", sum);
}
本文提供了一道来自PATest平台的L1-008题目的解决方案,采用C++语言实现。代码中展示了如何使用标准输入输出进行数据交互,并通过循环来计算指定范围内的整数之和。
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