Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
12 + 92 = 82
82 + 22 = 68
62 + 82 = 100
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
12 + 92 = 82
82 + 22 = 68
62 + 82 = 100
12 + 02 + 02 = 1
思路:每个数总能转变成一个10以内的数,因此判断这个数是不是可以的就行了,10以内只有1和7是happy number,因此程序就很简单了
代码:
class Solution {
public:
bool isHappy(int n) {
vector<int> num;
while(n>9){
while(n){
num.push_back(n%10);
n/=10;
}
for(int e:num){
n+=(e*e);
}
num.clear();
}
if(n==1||n==7)
return true;
else
return false;
}
};