Least Common Multiple

Description
The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.


Input
Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.

Output
For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.

Sample Input
2
3 5 7 15
6 4 10296 936 1287 792 1

Sample Output
105

10296


#include<cstdio>
using namespace std;

int fun(int a, int b)
{
	if (a%b != 0)
		return fun(b, a%b);
	else
		return b;
}
int main()
{
	int n;
	while (scanf("%d", &n) != EOF)
	{
		for (int i = 0; i < n; i++)
		{
			int num, ans, temp;
			scanf("%d", &num);
			scanf("%d", &ans);
			for (int i = 1; i < num; i++)
			{
				scanf("%d", &temp);
				ans = ans / fun(ans, temp)*temp;
			}
			printf("%d\n", ans);
		}
	}
}


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值