HDU1001

Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.


Input
The input will consist of a series of integers n, one integer per line.


Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.


Sample Input
1
100


Sample Output
1

5050

#include<iostream>
using namespace std;
int main2()
{
	int temp;
	while (cin >> temp)
	{
		int sum = 0;
		for (int j = 1; j <= temp; ++j)
		{
			sum += j;
		}
		cout << sum << endl;
		cout << endl;
	}
	return 0;
}