Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class Solution {
public:
int singleNumber(int A[], int n) {
int rtv = 0;
for(int i = 0; i < n; ++i)
rtv ^= A[i];
return rtv;
}
};
本文介绍了一种算法,该算法能在O(n)的时间复杂度内从整数数组中找出仅出现一次的整数。文章提供了一个具体的C++实现案例,通过按位异或操作实现了不使用额外内存的目标。
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