题目描述
Behind the scenes in the computer's memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 800x600), you are supposed to point out the strictly dominant color.
输入描述:
Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (<=800) and N (<=600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0, 224). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.
输出描述:
For each test case, simply print the dominant color in a line.
输入例子:
5 3 0 0 255 16777215 24 24 24 0 0 24 24 0 24 24 24
输出例子:
24
#include <iostream>
#include <map>
using namespace std;
int main() {
int m, n; //n是行数,m是每行的颜色
int x;
cin >> m >> n;
map<int, int> temp;
for (int i = 0; i < n * m; i++) {
cin >> x;
temp[x]++;
if (temp[x] >= m * n / 2) {
cout << x;
return 0;
}
}
return 0;
}
本文介绍了一个算法,用于从给定分辨率的图像中找出占据超过一半面积的严格主导颜色。该算法通过遍历每个像素并计数每种颜色出现的次数来实现。
433

被折叠的 条评论
为什么被折叠?



