1005Spell It Right (20)

最新推荐文章于 2024-05-17 16:45:04 发布

菜狗CaiDog

最新推荐文章于 2024-05-17 16:45:04 发布

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CC 4.0 BY-SA版权

本文链接：https://blog.youkuaiyun.com/BroKindey/article/details/81168744

本文介绍了一个简单的程序设计任务：给定一个非负整数N，计算其所有位数的和，并将每位数字的和用英文单词形式输出。程序通过读取用户输入的数字字符串，逐位计算总和，并使用预先定义的数组来转换成英文表述。

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题目描述

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

输入描述:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10100).

输出描述:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

输入例子:

输出例子:

one five

#include <iostream>
using namespace std;

int main() {
string number[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
char x[101] = {0};
int y = 0;
cin >> x;
for (int i = 0; i < 101; i++) {
if (x[i] == '\0') {
break;
}
else
y = y + x[i] - 48;
}
if (y / 100 != 0) {
cout << number[y / 100] << " " << number[y % 100 / 10] << " " << number[y % 10];
}
else if (y / 10 != 0) {
cout << number[y / 10] << " " << number[y % 10];
}
else {
cout << number[y];
}
return 0;
}