class Solution {
public:
/**
* @param nodes a array of Undirected graph node
* @return a connected set of a Undirected graph
*/
// BFS
vector<vector<int>> connectedSet1(vector<UndirectedGraphNode*>& nodes) {
// Write your code here
vector<vector<int>> result;
unordered_map<UndirectedGraphNode *, bool> map;// if visited or not
for(UndirectedGraphNode * node : nodes){
if(map.find(node) != map.end()){
continue;
}
queue<UndirectedGraphNode*> q;
q.push(node);
map[node] = true;
vector<int> row;// 一个子图 或者说 一个group节点
while(!q.empty()){
UndirectedGraphNode * now = q.front();
q.pop();
row.push_back(now->label);
for(in
通过BFS 和 DFS两种方法找无向图的连通分量
最新推荐文章于 2024-04-26 21:32:04 发布