问题 D: String Subtraction (20)

问题 D: String Subtraction (20)

时间限制: 1 Sec  内存限制: 32 MB
提交: 516  解决: 243
[提交][状态][讨论版][命题人:外部导入]

题目描述

Given two strings S1 and S2, S = S1 - S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1 - S2for any given strings. However, it might not be that simple to do it fast.

输入

Each input file contains one test case. Each case consists of two lines which gives S1 and S2, respectively. The string lengths of both strings are no more than 104. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

输出

For each test case, print S1 - S2 in one line.

样例输入

They are students.
aeiou

样例输出

Thy r stdnts.

 

需要注意的是

1. 只有一个输入案例
2.最后一行不能换行，不然输出超限

#include<cstdio>
#include<cstring>

const int maxn = 10010; 


int main(){
	char s1[maxn],s2[maxn];
		gets(s1);
		gets(s2);
		int  hashTable[127]={0};   //ASCII码对应的整型数只有0-127
		for(int i=0;i<strlen(s2);i++){
			hashTable[s2[i]]++;
		}
		for(int i=0;i<strlen(s1);i++){
			if(hashTable[s1[i]]==0)
			printf("%c",s1[i]);
	}
	return 0;
}