1065. A+B and C (64bit) (20)
时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B
判题程序 Standard 作者 HOU, Qiming
Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C.
Input Specification:
The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line “Case #X: true” if A+B>C, or “Case #X: false” otherwise, where X is the case number (starting from 1).
Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false
#include <iostream>
#include <fstream>
#include <cmath>
using namespace std;
int main()
{
#ifdef _DEBUG
ifstream cin("data.txt");
#endif // _DEBUG
long long A, B, C ,res;
int n,flag;
cin >> n;
for (int i = 1; i <= n; ++i)
{
cin >> A >> B >> C;
res = A + B;
if (A > 0 && B > 0 && res <= 0)flag = 1;//上溢
else if (A < 0 && B < 0 && res >= 0)flag = 0;//下溢
else if (res > C)flag = 1;
else flag = 0;
cout << "Case #" << i << ((flag) ? (": true") : (": false")) << endl;
}
#ifdef _DEBUG
cin.close();
system("pause");
#endif // _DEBUG
return 0;
}
#include <iostream>
#include <fstream>
#include <cmath>
using namespace std;
int main()
{
#ifdef _DEBUG
ifstream cin("data.txt");
#endif // _DEBUG
int T;
cin >> T;
for (int i = 1; i <= T; ++i)
{
long double a, b, c, ans;
cin >> a >> b >> c;
cout << "Case #" << i << ": " << (a + b>c ? "true" : "false") << endl;
}
#ifdef _DEBUG
cin.close();
system("pause");
#endif // _DEBUG
return 0;
}