1003 - Sibonacci Numbers

1003 - Sibonacci Numbers

Time Limit: 1s Memory Limit: 64MB

Submissions: 2130 Solved: 360

Description

As is known to all, the definition of Fibonacci Numbers is: f(1)=1 f(2)=1 f(n)=f(n-1)+f(n-2) (n>=3) Now Sempr found another Numbers, he named it "Sibonacci Numbers", the definition is below: f(x)=0 (x<0) f(x)=1 (0<=x<1) f(x)=f(x-1)+f(x-3.14) (x>=1) Your work is to tell me the result of f(x), is the answer is too large, divide it by 1000000007 and give me the remainder. Be careful the number x can be an integer or not.

Input

In the first line there is an Integer T(0<T<10000) which means the number of test cases in the input file. Then followed T different lines, each contains a number x(-1000<x<1000).

Output

For each case of the input file, just output the result, one for each line.

Sample Input

3
-1
0.667
3.15

Sample Output

0
1
2

#include<stdio.h>
#define MAXN 100000
int a[MAXN];
 
int main()
{
    int t,i,k;
    double x;
    for(i=0;i<314;i++)
    {
        a[i]=1;
    }
    for(i=314;i<MAXN;i++)
    {
        a[i]=a[i-100]+a[i-314];
        a[i]%=1000000007;
    }
    scanf("%d",&t);
    while(t--)
    {
        scanf("%lf",&x);
        if(x<0)
        {
            printf("0\n");
            continue;
        }
        x*=100;
        k=(int)(x+0.000001);
        printf("%d\n",a[k]);
    }
    return 0;
}