1005 Jugs

直接用暴力求解法，每次都是将B中的水逐步的往A中倒，一直到B中的水的体积是我们所要求解的量即可。

// C++Exercise.cpp : 定义控制台应用程序的入口点。
//

#include<iostream>
#include<string>
#include<stack>
using namespace std;

int Ca, Cb, N;

int main(){
	while (cin >> Ca >> Cb >> N){
		if (N == Ca){
			cout << "fill A" << endl << "success" << endl;
		}
		else if (N == Cb){
			cout << "fill B" << endl << "success" << endl;
		}
		else{
			cout <<"fill B" << endl << "pour B A" << endl;
			int temp = Cb - Ca;
			while (temp != N){
				cout << "empty A" << endl;
				if (temp < Ca){
					temp = Cb - (Ca - temp);
					cout << "pour B A" << endl << "fill B" << endl << "pour B A" << endl;
				}
				else{
					temp = temp - Ca;
					cout << "pour B A"<<endl;
				}
			}
			cout << "success" << endl;
		}
	}
	return 0;
}