Given a binary tree, return the preorder traversal of its nodes’ values.
Have you met this question in a real interview? Yes
Example
Given:
1
/ \
2 3
/ \
4 5
return [1,2,4,5,3].
/**
* Definition of TreeNode:
* public class TreeNode {
* public int val;
* public TreeNode left, right;
* public TreeNode(int val) {
* this.val = val;
* this.left = this.right = null;
* }
* }
*/
public class Solution {
public ArrayList<Integer> preorderTraversal(TreeNode root) {
ArrayList<Integer> result = new ArrayList<Integer>();
// null or leaf
if (root == null) {
return result;
}
// Divide
ArrayList<Integer> left = preorderTraversal(root.left);
ArrayList<Integer> right = preorderTraversal(root.right);
// Conquer
result.add(root.val);
result.addAll(left);
result.addAll(right);
return result;
}
}