Microsoft

Microsoft题目一，找出数字1在某设定范围的出现次数

如1-12 出现5次 1,2,3,4,5,6,7,8,9,10,11,12

1%10=1； 2%10=2， 3%10=3, 4%10=4，   1/10=0；2/10=0, 3/10=0

10%10=0, 11%10=1, 12%10=2, 

10/10=1, 11/10=1, 12/10=1, 

 

import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.IOException; class test2 { public static void main(String[] args)throws Exception { int s = 1; int t = 0; int d = 0; int count= 0; int count1= 0; int count2= 0; BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); System.out.println("Pleae input a end number:"); String input = reader.readLine(); int num = Integer.parseInt(input); for(int i=1;i<=num;i++) { t=s%10; d=s/10; if(t==1) { count1= count1+1; } if(d==1) { count2=count2+1; } s=s+1; count=count1+count2; } System.out.println("total have:..." +count+ " ...number 1"); } }

 

Microsoft 题目 阶乘 1-1000

import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.IOException; import java.math.BigInteger;//导入数学包中的biginter类 public class Test { public static void main(String[] args) throws IOException { BufferedReader reader=new BufferedReader(new InputStreamReader(System.in));//实例化新的缓存读取类 System.out.print("Please input a number(1-1000):"); String input=reader.readLine();//获取输入的内容 (String类型) int num = Integer.parseInt(input);//将String型软换为Int型 BigInteger s = BigInteger.valueOf(1);//声明s（BigInter型）并赋初始值1 for (int i = 1; i <= num; i++) { s = s.multiply(BigInteger.valueOf(i));//导入BigInter类中的方法，用于阶乘 } System.out.println("factorial result is:" + s); //System.out.println(s); } }