Have Fun with Numbers

Have Fun with Numbers

Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly the numbers from 1 to 9, only in a different permutation. Check to see the result if we double it again!

Now you are suppose to check if there are more numbers with this property. That is, double a given number with k digits, you are to tell if the resulting number consists of only a permutation of the digits in the original number.

Input Specification:
Each input contains one test case. Each case contains one positive integer with no more than 20 digits.

Output Specification:
For each test case, first print in a line “Yes” if doubling the input number gives a number that consists of only a permutation of the digits in the original number, or “No” if not. Then in the next line, print the doubled number.

Sample Input:

1234567899

Sample Output:

Yes
2469135798

题目解析

输入一串数字，最多20个，判断这串数字乘以2后得到的另一串数字的位数是否与原先相同，且是否是由原先数字组成的。数字相比，多一个不行，少一个不行。相同yes，不同no
例：原本921，三位。变化后，1842。位数不同，且数字不是由原来的数字变换位置组成的。

数字过大，用数组，单个单个数字解决更为妥当。
第一遍提交出错了，由于没考虑位数不同后的输出，要把多出的那位也输出出来，直接有针对的解决，看第一位数的2倍，除以10后是不是0。
是0说明位数没有增加，正常输出。
不是0，则说明位数增加，把这个数先输出，在输出变化后的数组。

public class Program
{
   
    public static void Main()
    {
   
        string line;
        while ((line = System.Console.ReadLine(