public int digitCounts(int k, int n) {
int count = 0;
char kChar = (char)(k + '0');
for (int i = k; i <= n; i++) {
char[] iChars = Integer.toString(i).toCharArray();
for (char iChar : iChars) {
if (kChar == iChar) count++;
}
}
return count;
}
digitCounts 统计0-n之间k字符出现的个数
最新推荐文章于 2024-05-17 02:02:20 发布