1000 - A+B Problem
大家好,这是我第一次上传
//今年我上初一下册
A+B的代码
题目:
1000 - A+B Problem
输入两个数字,输出它们之和
Input
一行两个数字A,B(0<=A,B<100)
Output
输出这两个数字之和
Examples//例子
input(输入)
1 2
output(输出)
3
Hint
Q: Where are the input and the output?
A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use ‘scanf’ in C or ‘cin’ in C++ to read from stdin, and use ‘printf’ in C or ‘cout’ in C++ to write to stdout. You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a “Wrong Answer”. User programs are not allowed to open and read from/write to files. You will get a “Runtime Error” or a “Wrong Answer” if you try to do so. Here is a sample solution for problem 1000 using C++/G++:**
主要的框架
C++
#include<iostream>//最基础的
or
#include <bits/stdc++.h>//万能头文件
C++的
#include
using namespace std;
int main()
{
int a,b;//申请a和b
cin >> a >> b;//输入a和b
cout << a+b << endl;//输出a+b
return 0;
}
C/C++
#include <stdio.h>
int main()
{
int a,b;
scanf("%d %d",&a, &b);//各式对称,同上,只是指令不一样
printf("%d\n",a+b);
return 0;
}
PASCAL
program p1000(Input,Output);
var
a,b:Integer;
begin
Readln(a,b);
Writeln(a+b);
end.
JAVA
import java.io.*;
import java.util.*;
public class Main
{
public static void main(String args[]) throws Exception
{
Scanner cin=new Scanner(System.in);
int a=cin.nextInt(),b=cin.nextInt();
System.out.println(a+b);
}
}
老版JAVA
import java.io.*;
import java.util.*;
public class Main
{
public static void main (String args[]) throws Exception
{
BufferedReader stdin =
new BufferedReader(
new InputStreamReader(System.in));
String line = stdin.readLine();
StringTokenizer st = new StringTokenizer(line);
int a = Integer.parseInt(st.nextToken());
int b = Integer.parseInt(st.nextToken());
System.out.println(a+b);
}
}
谢谢大家能看我的作品//过不去的可以私聊我
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