【Leetcode】Best Time to Buy and Sell Stock I

最新推荐文章于 2025-12-04 16:02:12 发布

转载最新推荐文章于 2025-12-04 16:02:12 发布 · 303 阅读

文章标签：

#leetcode #java #array

本文介绍了一种寻找股票买卖最佳时机以获得最大利润的算法。该算法通过一次遍历即可得出最优解，提供了两种实现方式：一是维护局部最优和全局最优；二是记录最低价格和以此为基础的最大利润。

Best Time to Buy and Sell Stock

Say you have an array for which the ith element is the price of a given stock on day i.

If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit.

Java:

1. CodeGanker http://blog.youkuaiyun.com/linhuanmars/article/details/23162793

维护两个量局部最优全局最优

public int maxProfit(int[] prices) {
    if(prices==null || prices.length==0)
        return 0;
    int local = 0;
    int global = 0;
    for(int i=0;i<prices.length-1;i++)
    {
        local = Math.max(local+prices[i+1]-prices[i],0);
        global = Math.max(local, global);
    }
    return global;
}

2. 改良： http://blog.youkuaiyun.com/u013027996/article/details/19414967

public class Solution {
    public int maxProfit(int[] prices) {  
        if(prices == null || prices.length == 0){  
            return 0;  
        }  
        int len = prices.length;  
        int maxProfit = 0, min=prices[0];  
        for(int i = 1; i < len; i++){  
            int tempProfit = prices[i] - min;  
            if(maxProfit < tempProfit){  
                maxProfit = tempProfit;  
            }  
            if(min > prices[i]){  
                min = prices[i];  
            }  
        }  
        return maxProfit;  
    }  
}