# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def levelOrder(self, root: TreeNode) -> List[List[int]]:
if not root:return []
queue,res = [],[]
queue.append(root)
while queue:
cl = []
for _ in range(len(queue)):
node = queue.pop(0)
cl.append(node.val)
if node.left:queue.append(node.left)
if node.right:queue.append(node.right)
res.append(cl)
return res
leetcode 二叉树的层序遍历 python3
最新推荐文章于 2025-02-11 14:32:44 发布