[Leetcode]Count and Say

The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.

Given an integer n, generate the nth sequence.

Note: The sequence of integers will be represented as a string.

如果有更好更高效的代码，希望大家共享~

class Solution {
public:
    string countAndSay(int n) {
        string seq = "1";
        string result = "";
        int count = 1;
        char pre;
        if(n > 1)
        {
            for (int i = 2; i <= n; i++)
            {
                pre = ' ';
                for (int j = 0; j < seq.size(); j++)
                {
                    if(j + 1 < seq.size() && seq[j + 1] == seq[j])
                    {
                        count++;
                    }
                    else
                    {
                        pre = seq[j];
                        result.push_back(count + '0');
                        result.push_back(pre);
                        count = 1;
                    }
                }
                seq = result;
                result = "";
            }
            return seq;
        }
        else if(n == 1)
        {
            return "1";
        }
    }
};

本文不详尽或错误之处，请各位不吝言辞，多多指教~谢谢~

             作者：Louise http://blog.youkuaiyun.com/yupingliu