HDU_2055 An easy problem

An easy problem

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 

 

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

 

 

Output

for each case, you should the result of y+f(x) on a line.

 

 

Sample Input

  
  

   
   6
R 1
P 2
G 3
r 1
p 2
g 3
  
  

 

 

Sample Output

  
  

   
   19
18
10
-17
-14
-4
  
  

 

#include<stdio.h>

int main()
{
	int n,x,i;
	char str;
	scanf("%d",&n);
	getchar();       //注意 
	while(n--)
	{
		scanf("%c%d",&str,&x);
		getchar();
		if(str>='a'&&str<='z')
			printf("%d\n",'a'-str+x-1);
		else if(str>='A'&&str<='Z')
			printf("%d\n",str-'A'+x+1);
	}
	return 0;
}