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A+B Problem II
时间限制:3000 ms | 内存限制:65535 KB
难度:3
描述
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
A,B must be positive.
输入
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
输出
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation.
样例输入
2 1 2 112233445566778899 998877665544332211
样例输出
Case 1: 1 + 2 = 3 Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110
import java.math.*;
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner num = new Scanner(System.in);
int n = num.nextInt();
for(int i=1; i<=n; i++){
BigInteger a = num.nextBigInteger();
BigInteger b = num.nextBigInteger();
//System.out.println();
System.out.println("Case "+i+":");
System.out.println(a+" + "+b+" = "+a.add(b));
}
}
}