A+B Problem II

A+B Problem II

时间限制： 3000 ms  |  内存限制： 65535 KB

难度： 3

描述

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

A,B must be positive.

输入

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

输出

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation.

样例输入

2
1 2
112233445566778899 998877665544332211

样例输出

Case 1:
1 + 2 = 3
Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

import java.math.BigInteger;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);
		int number = scanner.nextInt();
		int count = 0;
		while (number-- != 0) {
			count++;
			System.out.println("Case " + count + ":");
			BigInteger numone = scanner.nextBigInteger();
			BigInteger numtwo = scanner.nextBigInteger();
			System.out.println(numone + " + " + numtwo + " = " + numone.add(numtwo));
		}
	}
}