1082 Read Number in Chinese (25)

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. For example, -123456789 is read as "Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu". Note: zero ("ling") must be handled correctly according to the Chinese tradition. For example, 100800 is "yi Shi Wan ling ba Bai".

Input Specification:

Each input file contains one test case, which gives an integer with no more than 9 digits.

Output Specification:

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.

Sample Input 1:

-123456789

Sample Output 1:

Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu

Sample Input 2:

100800

Sample Output 2:

yi Shi Wan ling ba Bai

思路：

用中文拼音输出数字

C++：

#include<cstdio>
#include<cstring>

char num[10][5]={
	"ling","yi","er","san","si","wu","liu","qi","ba","jiu" 
};
char wei[5][5]={
	"Shi","Bai","Qian","Wan","Yi"
};

int main(){
	char str[15];
	gets(str);
	int len=strlen(str);
	int left=0,right=len-1;
	if(str[0]=='-'){//为负数
		printf("Fu");
		left++;
	}
	while(left+4<=right){//让left、right在同一个小节中
		right-=4;
	}
	while(left<len){
		bool flag=false;//记录是否有累积零
		bool isPrint=false;
		while(left<=right){
			if(left>0&&str[left]=='0'){//有零
				flag=true;
			}else{//第一个不为零的数
				if(flag==true){
					printf(" ling");
					flag=false;
				}
				if(left>0)printf(" ");
				printf("%s",num[str[left]-'0']);
				isPrint=true;
				if(left!=right){//除个位 别的位皆要输出千百十
					printf(" %s",wei[right-left-1]);
				}
			}
			left++;
		}
		if(isPrint==true&&right!=len-1){
			printf(" %s",wei[(len-1-right)/4+2]);
		}
		right+=4;
	}
	return 0;
}