Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
For example,
Given n = 3
,
[ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ]Array
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class Solution {
public:
vector<vector<int>> res;
vector<vector<int> > generateMatrix(int n) {
if(n<0)
return res;
else if(n==1)
{
vector<int> tmp;
tmp.push_back(1);
res.push_back(tmp);
return res;
}
int ** arr=new int*[n];
for(int i=0;i<n;i++)
{
arr[i]=new int[n];
memset(arr[i],0,sizeof(int)*n);
}
//vector<int> bit(n*n,0);
int count=0;
int num=1;
int x=0;
int y=-1;
while(num<=n*n)
{
if(count==0)
{
y++;
while(y<n&&arr[x][y]==0)
{
arr[x][y]=num++;
y++;
}
count=(count+1)%4;
y--;
}
else if(count==1)
{
x++;
while(x<n&&arr[x][y]==0)
{
arr[x][y]=num++;
x++;
}
count=(count+1)%4;
x--;
}
else if(count==2)
{
y--;
while(y>=0&&arr[x][y]==0)
{
arr[x][y]=num++;
y--;
}
count=(count+1)%4;
y++;
}
else if(count==3)
{
x--;
while(x>=0&&arr[x][y]==0)
{
arr[x][y]=num++;
x--;
}
count=(count+1)%4;;
x++;
}
}
for(int i=0;i<n;i++)
{
vector<int> tmp;
for(int j=0;j<n;j++)
tmp.push_back(arr[i][j]);
res.push_back(tmp);
}
return res;
}
};