题目描述:
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
代码如下:public class Solution {
public int minPathSum(int[][] grid) {
int m = grid.length;
int n = grid[0].length;
int[][] dp = new int[m][n];
dp[0][0] = grid[0][0];
for(int j = 1;j<n;j++){
dp[0][j] = dp[0][j-1] + grid[0][j];
}
for(int i = 1;i<m;i++){
dp[i][0] = dp[i-1][0] + grid[i][0];
}
for(int j = 1;j<n;j++){
for(int i = 1;i<m;i++){
dp[i][j] = Integer.min(dp[i-1][j],dp[i][j-1])+grid[i][j];
}
}
return dp[m-1][n-1];
}
}
本文介绍了一个经典算法问题——寻找矩阵中从左上角到右下角路径的最小累积值,仅允许向右或向下移动。文章通过动态规划的方法详细阐述了如何高效地解决这一问题,并提供了完整的Java实现代码。
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