CodeForce 651 A Joysticks

C - Joysticks

Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u

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Description

Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at a₁ percent and second one is charged at a₂ percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if not connected to a charger) or charges by 1 percent (if connected to a charger).

Game continues while both joysticks have a positive charge. Hence, if at the beginning of minute some joystick is charged by 1 percent, it has to be connected to a charger, otherwise the game stops. If some joystick completely discharges (its charge turns to 0), the game also stops.

Determine the maximum number of minutes that game can last. It is prohibited to pause the game, i. e. at each moment both joysticks should be enabled. It is allowed for joystick to be charged by more than 100 percent.

Input

The first line of the input contains two positive integers a₁ and a₂ (1 ≤ a₁, a₂ ≤ 100), the initial charge level of first and second joystick respectively.

Output

Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged.

Sample Input

Input

3 5

Output

6

Input

4 4

Output

5

题意：有两个游戏手柄，分别有百分之a1和百分之a2的电量，在不充电的情况下，每分钟消耗百分之二的点，充电的情况下，每分钟冲百分之一的电量现在只有一个充电器，问能持续多长时间。

#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
int main()
{
	int a1,a2,time;
	while(scanf("%d%d",&a1,&a2)!=EOF)
	{
		time=0;
		while(a1>0&&a2>0)
		{
			if(a1==1&&a2==1)//刚开始忘记考虑了。。 
			break;
			if(a1>a2)
			{
				a1=a1-2;
				a2=a2+1;
			}
			else
			{
				a1=a1+1;
				a2=a2-2;
			}
			time++;
		}
		printf("%d\n",time);
	 } 
	 return 0;
}