An easy problem
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 19028 Accepted Submission(s): 12700
Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
Give you a letter x and a number y , you should output the result of y+f(x).
Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
Output
for each case, you should the result of y+f(x) on a line.
Sample Input
6 R 1 P 2 G 3 r 1 p 2 g 3
Sample Output
19 18 10 -17 -14 -4
Author
8600
Source
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字符输入时要注意
#include<stdio.h>
#include<string.h>
int main()
{
int i,j,m,t;
char n;
scanf("%d",&t);
while(t--)
{
getchar();
scanf("%c%d",&n,&m);
if(n>=65&&n<=90)
printf("%d\n",m+n-'A'+1);
else
printf("%d\n",m-n+'a'-1);
}
}