如何查询时去除重复数据?并且删除重复记录
比如现在有一人员表 (表名:peosons)
若想将姓名、身份证号、住址这三个字段完全相同的记录查询出来
select p1.*
from persons p1,persons p2
where p1.id<>p2.id
and p1.cardid = p2.cardid and p1.pname = p2.pname and p1.address = p2.address
(1)用rowid方法
(2)用group by方法
据据oracle带的rowid属性,进行判断,是否存在重复,语句如下:
查询重复的数据:
select * from table1 a where rowid !=(select max(rowid)
复制代码 代码如下:
delete from table1 a where rowid !=(select max(rowid)
查数据:
select count(num), max(name) from student --列出重复的记录数,并列出他的name属性
group by num
delete from student
group by num
having count(num) >1
create table table_new as select distinct * from table1 minux
truncate table table1;
比如现在有一人员表 (表名:peosons)
若想将姓名、身份证号、住址这三个字段完全相同的记录查询出来
select p1.*
from persons p1,persons p2
where p1.id<>p2.id
and p1.cardid = p2.cardid and p1.pname = p2.pname and p1.address = p2.address
可以实现上述效果.
(1)用rowid方法
(2)用group by方法
(3)用distinct方法
据据oracle带的rowid属性,进行判断,是否存在重复,语句如下:
查询重复的数据:
select * from table1 a where rowid !=(select max(rowid)
from table1 b where a.name1=b.name1 and a.name2=b.name2......)
删重复的数据:复制代码 代码如下:
delete from table1 a where rowid !=(select max(rowid)
from table1 b where a.name1=b.name1 and a.name2=b.name2......)
查数据:
select count(num), max(name) from student --列出重复的记录数,并列出他的name属性
group by num
having count(num) >1 --按num分组后找出表中num列重复,即出现次数大于一次
删数据:delete from student
group by num
having count(num) >1
这样的话就把所有重复的都删除了。
create table table_new as select distinct * from table1 minux
truncate table table1;
insert into table1 select * from table_new;