题目
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
思路
所有数字异或,得到的最后的数字就是所求。
代码
class Solution:
def singleNumber(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
result = 0
for num in nums:
result ^= num
return result