hbmy周赛1--A

最新推荐文章于 2022-11-21 16:45:10 发布

原创最新推荐文章于 2022-11-21 16:45:10 发布 · 668 阅读

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#周赛

本文介绍了一个简单的年龄排序问题及其解决方案。任务是接收一系列年龄输入（不超过99岁），使用自定义比较函数对这些年龄进行升序排列，并输出排序后的年龄列表。文章提供了完整的C++代码实现，展示了如何通过标准模板库(STL)的sort函数来高效地完成任务。

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Age Sort

You are given the ages (in years) of all people of a country with at least 1 year of age. You know thatno individual in that country lives for 100 or more years. Now, you are given a very simple task ofsorting all the ages in ascending order.

Input

There are multiple test cases in the input file. Each case starts with an integer n (0 < n ≤ 2000000), thetotal number of people. In the next line, there are n integers indicating the ages. Input is terminatedwith a case where n = 0. This case should not be processed.

Output

For each case, print a line with n space separated integers. These integers are the ages of that countrysorted in ascending order.Warning: Input Data is pretty big (∼ 25 MB) so use faster IO.

Sample Input

3 4 2 1 5

2 3 2 3 1

Sample Output

1 2 3 4 5

1 2 2 3 3

#include <iostream>
#include <stdio.h>
#include <algorithm>
using namespace std;

int compare(int x, int y)
{
	return x < y;
}

int a[2000010];

int main()
{
	int n;
	while (scanf("%d",&n) && n)
	{
		for (int i=0; i<n; i++)
			scanf("%d",&a[i]);
		sort(a,a+n,compare);
		printf("%d",a[0]);
		for (int i=1; i<n; i++)
			printf(" %d",a[i]);
		printf("\n");
	}
	return 0;
	
}