解析字符串为时间
Java休眠
SimpleDateFormat 类有一些附加的方法,特别是parse(),它试图按照给定的SimpleDateFormat 对象的格式化存储来解析字符串
import java.util.*;
import java.text.*;
public class DateDemo {
public static void main(String args[]) {
SimpleDateFormat ft = new SimpleDateFormat ("yyyy-MM-dd");
String input = args.length == 0 ? "1818-11-11" : args[0];
System.out.print(input + " Parses as ");
Date t;
try {
t = ft.parse(input);
System.out.println(t);
} catch (ParseException e) {
System.out.println("Unparseable using " + ft);
}
}
}
Java休眠
import java.util.*;
public class SleepDemo {
public static void main(String args[]) {
try {
System.out.println(new Date( ) + "\n");
Thread.sleep(1000*3); // 休眠3秒
System.out.println(new Date( ) + "\n");
} catch (Exception e) {
System.out.println("Got an exception!");
}
}
}