编写解决方案找出合作过至少三次的演员和导演的 id 对 (actor_id, director_id)。
import pandas as pd
def actors_and_directors(actor_director: pd.DataFrame) -> pd.DataFrame:
df = actor_director.groupby(['actor_id','director_id']).size().reset_index(name='counts')
return df[df['counts']>=3][['actor_id','director_id']]