Nim Game: https://leetcode.com/problems/nim-game/
n是4的倍数时一定失败
add digits: https://leetcode.com/problems/add-digits/
return 1 + (num - 1) % 9;
Factorial Trailing Zeros: https://leetcode.com/problems/factorial-trailing-zeroes/
返回5^1的个数 + 5^2的个数 + ... + 5^i的个数,其中5^(i+1) > n。从n开始依次÷5倒着往下比较快,并且保证数据不会溢出