Given an integer n, return the number of trailing zeroes in n!.
Example 1:
Input: 3
Output: 0
Explanation: 3! = 6, no trailing zero.
Example 2:
Input: 5
Output: 1
Explanation: 5! = 120, one trailing zero.
public class Solution {
public int trailingZeroes(int n) {
int res = 0;
double p5 = 5;
while(n >= p5) {
res += n / p5;
p5 *= 5;
}
return res;
}
}