1001. A+B Format (20)

最新推荐文章于 2024-06-13 15:02:42 发布

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本文介绍了一个C++程序，该程序接收两个整数输入，并计算它们的和。计算结果将按照标准格式输出，即每三个数字插入一个逗号以增强可读性。程序考虑了各种边界情况，如负数和零。

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Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

提交代码

用数组每三位存一个,注意和为0的情况

#include <iostream>
#include <stdio.h>
#include <algorithm>
#include <string.h>
#include <string>
#include <cmath>

int res[3];

using namespace std;

int main(){
    int a,b;
    cin>>a>>b;
    int ans=a+b;
    if(ans<0){
        printf("-");
        ans=-ans;
    }
    int cnt=0;
    if(ans==0)
        printf("%d",ans);
    else{
        while(ans){
            res[cnt++]=ans%1000;
            ans/=1000;
        }
        int temp=cnt-1;
        int flag=0;
        for(int i=cnt-1;i>=0;i--){
            if(flag++)
                printf("%03d",res[i]);
            else
                printf("%d",res[i]);
            if(temp--){
                printf(",");
            }
        }
    }
    return 0;
}