hivesql连续日期统计最大逾期/未逾期案例

1、虚表(测试表和数据) create test_table as

select a.cust_no, a.r_date, a.yqts from  (

select '123' as cust_no, '20231101' as r_date, 0 as yqts

union all

select '123' as cust_no, '20231102' as r_date, 1 as yqts

union all

select '123' as cust_no, '20231103' as r_date, 2 as yqts

union all

select '123' as cust_no, '20231104' as r_date, 3 as yqts

union all

select '123' as cust_no, '20231105' as r_date, 0 as yqts

union all

select '123' as cust_no, '20231106' as r_date, 0 as yqts

union all

select '123' as cust_no, '20231107' as r_date, 1 as yqts

) a

2、加入有表test_table，数据如上，0标识未逾期，1标识逾期，求连续最大无逾期和逾期的天数，以上数据可直接看出最大连续逾期天数为3、未逾期未2。

3、首先将测试数据排序，让数据连续

select a.cust_no, a.r_date, a.yqts from test_table a where 1=1 order by a.cust_no, a.r_date asc

4、将数据分组并给是否逾期打上标识1逾期，2未逾期，多行转一行

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