Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).
You may assume that the intervals were initially sorted according to their start times.
Example 1:
Given intervals [1,3],[6,9]
, insert and merge [2,5]
in
as [1,5],[6,9]
.
Example 2:
Given [1,2],[3,5],[6,7],[8,10],[12,16]
, insert and merge [4,9]
in
as [1,2],[3,10],[12,16]
.
This is because the new interval [4,9]
overlaps with [3,5],[6,7],[8,10]
.
/**
* Definition for an interval.
* struct Interval {
* int start;
* int end;
* Interval() : start(0), end(0) {}
* Interval(int s, int e) : start(s), end(e) {}
* };
*/
class Solution {
public:
vector<Interval> insert(vector<Interval> &intervals, Interval newInterval) {
vector<Interval> result;
if(intervals.size() == 0)
{
result.push_back(newInterval);
return result;
}
for(int i = 0; i < intervals.size(); i++)
{
if(intervals[i].start > newInterval.start)
{
intervals.insert(intervals.begin() + i, newInterval);
break;
}
else if(i == intervals.size()-1)
{
intervals.push_back(newInterval);
break;
}
}
result.push_back(intervals[0]);
for(int i = 1; i < intervals.size(); i++)
{
if(result.back().end >= intervals[i].start)
{
result.back().end = std::max(result.back().end, intervals[i].end);
}
else
{
result.push_back(intervals[i]);
}
}
return result;
}
};
Round 2:
/**
* Definition for an interval.
* struct Interval {
* int start;
* int end;
* Interval() : start(0), end(0) {}
* Interval(int s, int e) : start(s), end(e) {}
* };
*/
class Solution {
public:
vector<Interval> insert(vector<Interval> &intervals, Interval newInterval) {
int indexS = -1, indexE = -1;
for(int i = 0; i < intervals.size(); i++)
{
if(newInterval.start >= intervals[i].start)
{
indexS = i;
}
if(newInterval.end >= intervals[i].start)
indexE = i;
}
if(indexE == -1)
intervals.insert(intervals.begin(), newInterval);
else
{
if(indexS != -1)
{
if(intervals[indexS].end >= newInterval.start)
{
newInterval.start = intervals[indexS].start;
}
else
indexS++;
}
else
indexS = 0;
newInterval.end = std::max(intervals[indexE].end, newInterval.end);
if(indexS < indexE+1)
intervals.erase(intervals.begin()+indexS, intervals.begin()+indexE+1);
intervals.insert(intervals.begin()+indexS, newInterval);
}
return intervals;
}
};